Java Given a Set of N Tasks,the Ith Task Runs From Time Start[i] Through End[i]. Implemet a Task Scheduler Method That Finds the Minimum Number of Machines Required to Complete the Tasks.
Java Given a Set of N Tasks,the Ith Task Runs From Time Start[i] Through End[i]. Implemet a Task Scheduler Method That Finds the Minimum Number of Machines Required to Complete the Tasks.
Full Title: Java Given a Set of N Tasks,the Ith Task Runs From Time Start[i] Through End[i]. Implemet a Task Scheduler Method That Finds the Minimum Number of Machines Required to Complete the Tasks.
Explanation:
To solve this problem, you can use the concept of interval scheduling, a common problem in computer science. The aim is to find the minimum number of machines required to complete all tasks without conflict. This requires a machine to run one task at a time, without overlap.
The algorithm to this problem is to sort the tasks by their end times and assign tasks to a machine if the machine is free at the task’s start time. Each time a new machine is needed, increment a counter. The counter represents the minimum number of machines required.
Here is a potential java implementation:
public int minMachines(int[][] tasks) {
Arrays.sort(tasks, (a, b) → a[1] - b[1]);
PriorityQueue queue = new PriorityQueue<>((a, b) → a[0] - b[0]);
for(int[] task : tasks) {
if(queue.isEmpty() || task[0] ⇐ queue.peek()[1])
queue.offer(task);
else {
queue.poll();
queue.offer(task);
}
}
return queue.size();
} (View Highlight)
